![]() ![]() And || expression will be evaluated at runtime, and the value will only be available at that time. That is only possible if the case value is a constant expression. In earlier versions, if you have to write conditional logic based on a string, you had to use. So, for the cases label to be used by tableswitch as a index into the table of target offsets, the value of the case should be known at compile time. Java 7 started support for using String in switch case. Each case statement can have a break statement which is optional. The Java switch expression must be of byte, short, int, long (with its Wrapper type), enums and string. In case of duplicate value, it renders compile-time error. ![]() The default target of the switch is used if the value of the expression of the switch falls outside the range of valid indices. The case value must be literal or constant. The tableswitch instruction is used when the cases of the switch can be efficiently represented as indices into a table of target offsets. Whatever case matches the value of variable, that block get executed and exit from the switch case block on break statement. switch ( value ), the value of variable is matched to case written in it body. The reason behind allowing just constant expression with cases can be understood from the JVM Spec Section 3.10 - Compiling Switches:Ĭompilation of switch statements uses the tableswitch and lookupswitch instructions. Switch case statement in java is also conditional statement. Switch label should have following syntax: And since an || expression is not a compile time constant, it is not allowed. ![]() What are the backgrounds for a switch-case to not accept this operator?īecause case requires constant expression as its value. If 'something' and 'something else' are in mixed cases, and come from variables, this wouldnt apply. ![]()
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